7k^2-32k+16=0

Solution for 7k^2-32k+16=0 equation:

7k^2-32k+16=0

a = 7; b = -32; c = +16;
Δ = b2-4ac
Δ = -322-4·7·16
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-24}{2*7}=\frac{8}{14}
=4/7
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+24}{2*7}=\frac{56}{14}
=4
$